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The sums of n terms of two arithmetic pr...

The sums of n terms of two arithmetic progresssions are in the ratio `(7n+1):(4n+17).` Find the ratio of their nth terms.

Text Solution

Verified by Experts

Given, `S_(n):S'_(n)=(7n+1):(4n+17)`
Here, `A=7,B=1,C=4 and D = 17 `
`therefore (t_(n))/(t'_n)=(7(2n-1)+1)/(4(2n-1)+17)=(14n-6)/(8n+13)`
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