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If cos (x-y),, cosx and cos(x+y) are in ...

If `cos (x-y),, cosx and cos(x+y)` are in H.P, then `cosx*sec(y/2)`=

A

`pmsqrt(2)`

B

`(1)/(sqrt(2))`

C

`-(1)/(sqrt(2))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`:.cos(x-y),cosx,cos(x+y)` are in HP.
`:.cosx=(2cos(x-y)cos(x+y))/(cos(x-y)+cos(x+y))`
`implies cosx=(2cos^(2)x-sin^(2)y)/(2cosx cosy)`
`implies cos^(2)x cosy =cos^(2)x-sin^(2)y`
`implies cos^(2)x(1-cosy)=sin^(2)y`
`=(1+cos y)(1-cosy )`
`implies cos^(2)x=(1+cosy)" "[:.1-cosyne0]`
`implies cos^(2)x= 2 cos^(2)""(y)/(2)`
`implies cos^(2)xsec^(2)((y)/(2))=2`
`:. cos x sec ((y)/(2))= pm sqrt(2)`
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