Home
Class 12
MATHS
If a(1),a(2),a(3),"......" be in harmoni...

If `a_(1),a_(2),a_(3),"......"` be in harmonic progression with `a_(1)=5` and `a_(20)=25`. The least positive integer n for which `a_(n)lt0` is

A

22

B

23

C

24

D

25

Text Solution

Verified by Experts

The correct Answer is:
D

`:.a_(1),a_(2),a_(3),"......."` are in HP.
`:.(1)/(a_(1)),(1)/(a_(2)),(1)/(a_(3)),"......."`
Let D be the common difference of this AP, then
`(1)/(a_(20))=(1)/(a_(1))+(20-1)D`
`implies D((1)/(25)-(1)/(5))/(19)=-(4)/(25xx19)`
and `(1)/(a_(n))=(1)/(a_(1))+(n-1)D=(1)/(5)-(4(n-1))/(25xx19)=((95-4n+4)/(25xx19))`
`=((99-4n)/(25xx19))lt0" " [:.a_(n)lt0]`
`implies 99-4nlt0 implies ngt24.75`.
Promotional Banner

Similar Questions

Explore conceptually related problems

If a_(1),a_(2),a_(3),"........" is an arithmetic progression with common difference 1 and a_(1)+a_(2)+a_(3)+"..."+a_(98)=137 , then find the value of a_(2)+a_(4)+a_(6)+"..."+a_(98) .

If a_(1),a_(2),a_(3),...,a_(n) is an arithmetic progression with common difference d, then evaluate the following expression. tan[tan^(-1)(d/(1+a_(1)a_(2)))+tan^(-1)(d/(1+a_(2)a_(3)))+...+tan^(-1)(d/(1+a_(n-1)*a_(n)))]

Let a_(1),a_(2),"...." be in AP and q_(1),q_(2),"...." be in GP. If a_(1)=q_(1)=2 " and "a_(10)=q_(10)=3 , then

A squence of positive terms A_(1),A_(2),A_(3),"....,"A_(n) satisfirs the relation A_(n+1)=(3(1+A_(n)))/((3+A_(n))) . Least integeral value of A_(1) for which the sequence is decreasing can be

If a_(1),a_(2),a_(3)(a_(1)gt0) are three successive terms of a GP with common ratio r, the value of r for which a_(3)gt4a_(2)-3a_(1) holds is given by

Let A_(1),A_(2),A_(3),"......."A_(m) be arithmetic means between -3 and 828 and G_(1),G_(2),G_(3),"......."G_(n) be geometric means between 1 and 2187. Product of geometric means is 3^(35) and sum of arithmetic means is 14025. The value of n is

Let A_(1),A_(2),A_(3),"......."A_(m) be arithmetic means between -3 and 828 and G_(1),G_(2),G_(3),"......."G_(n) be geometric means between 1 and 2187. Product of geometric means is 3^(35) and sum of arithmetic means is 14025. The value of m is

If a_(1),a_(2),a_(3),".....",a_(n) are in HP, than prove that a_(1)a_(2)+a_(2)a_(3)+a_(3)a_(4)+"....."+a_(n-1)a_(n)=(n-1)a_(1)a_(n)

If a_(1), a_(2), a_(3).,,,,,,,,a_(n) are in A.P and their common difference is d. The value of the series sin d_(1) [sec a_(1).sec a_(2) + sec a_(2).sec a_(3)+ ….+ sec a_(n-1).sec a_(n)] is……..

Show that a_(1),a_(2),......a_(n),.... from an AP where a_n is defined as below: (1)a_(n)=3+4n(2)a_(n)=9-5n Also find the sum of the first 15 terms in each case.