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Let P = [a(ij)] " be a " 3 xx 3 matrix a...

Let `P = [a_(ij)] " be a " 3 xx 3` matrix and let `Q = [b_(ij)], " where " b_(ij) = 2^(i +j) a_(ij) " for " 1 le i, j le 3`. If the determinant of P is 2, then the determinant of the matrix Q is

A

`2^(11)`

B

`2^(12)`

C

`2^(13)`

D

`2^(10)`

Text Solution

Verified by Experts

The correct Answer is:
C
We have, `abs(Q) = abs((2^(2) a_(11) ,2^(3)a_(12), 2^(4) a_(13)),(2^(3)a_(21),2^(4)a_(22),2^(5) a_(23) ),(2^(4)a_(31),2^(5)a_(32),2^(6)a_(33)))`
` =2^(2) cdot 2^(3)cdot2^(4) abs(( a_(11) ,a_(12), a_(13)),(2a_(21),2a_(22),2 a_(23) ),(2^(2)a_(31),2^(2)a_(32),2^(2)a_(33)))`
` =2^(9) cdot 2cdot2^(2) abs(( a_(11) ,a_(12), a_(13)),(a_(21),a_(22), a_(23) ),(a_(31),a_(32),a_(33))) = 2^(12) abs(P)`
`therefore abs(Q)=2^(12)xx2=2^(13)`
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