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(n>=5) persons are sitting in a row. Thr...

`(n>=5)` persons are sitting in a row. Three of these are selected at random. The probability that no two of the selected persons sit together is

A

`(.^(n-3)P_2)/(.^nP_2)`

B

`(.^(n-3)C_2)/(.^nC_2)`

C

`((n-3)(n-4))/(n(n-1))`

D

`(.^(n-3)C_2)/(.^nP_2)`

Text Solution

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The correct Answer is:
(a,b,c,d)
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