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A chess game between two grandmasters X ...

A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or loosing any perticular game are a, b and c, respectively. The games are independent and a+b+c=1.
The probability that Y wins the match after the 4th game, is

A

`abc(2a+3b)`

B

`bc^2(a+3b)`

C

`2ac^2(b+c)`

D

`3bc^2(2a+b)`

Text Solution

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The correct Answer is:
(d)
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