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Let n=10lambda+r", where " lambda,rinN,...

Let ` n=10lambda+r", where " lambda,rinN, 0lerle9.` A number a is chosen at random from the set {1, 2, 3,…, n} and let `p_n` denote the probability that `(a^2-1)` is divisible by 10.
If r=0, then `np_n` equals

A

(a) `2lambda`

B

(b) `(lambda+1)`

C

(c) `(2lambda+1)`

D

(d) `lambda`

Text Solution

Verified by Experts

The correct Answer is:
(a)
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