Solve the equation , sqrt(3) sin 2A = s...

Solve the equation , ` sqrt(3) sin 2A = sin 2B and sqrt(3)sin^(2)A + sin^(2)B=(1)/(2)(sqrt(3)-1)`.

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The correct Answer is:

`A=n pi pm (pi)/(12); B= n pi + (pi)/6`

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