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The equation sin^4 x + cos^4 x + sin2x +...

The equation `sin^4 x + cos^4 x + sin2x + alpha = 0` is solvable for

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The correct Answer is:
` alpha in [-(3)/(2),(1)/(2)] and x=(n x )/(2)+((-1)^(n))/(2)sin^(-1)(1-sqrt(2 alpha +3))`
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