Find the point of intersection of the curves `arg(z-3i)=(3pi)/4` and `arg(2z+1-2i)=pi/4.`

Find the point of intersection of the line (x-1)/(2)=(2-y)/(3)=(z+3)/(4) and the plane 2x + 4y - z = 1. Also find the angle between them.

The disatance of the point (1, 0, 2) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=16 , is

Find the equation of the plane containing the line of intersection of the plane x + y + z-6 = 0 and 2x + 3y + 4z + 5 = 0 and passing through the point (1, 1, 1).

Find the equation of a line which passes through the point (1,1,1) and intersects the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x+2)/1=(y-3)/2=(z+1)/4dot

The mirror image of the curve arg((z-3)/(z-i))=pi/6, i=sqrt(- 1) in the real axis

Find the equations of the two lines through the origin which intersect the line (x-3)/(2)=(y-3)/(1)=z/1 at angle of pi/3 each.

Find the equation of the plane through the intersection of the planes 3x – y + 2z – 4 = 0 and x + y + z- 2 = 0 and the point (2, 2, 1).

Find the intersection point of (x)/(1)=(y)/(2)=(z)/(2)and2x+y+z=6 .

Interpet the following equations geometrically on the Argand plane. arg(z+i)-arg(z-i)=(pi)/(2)