If w=alpha+ibeta where beta ne 0 and z ...

If `w=alpha+ibeta` where `beta ne 0 ` and `z ne 1` satisfies the condition that `((w- bar wz)/(1-z))` is purely real then the set of values of z is

A

`{z:abs(z)=1}`

B

`{z:z=bar(z)}`

C

`{z:z ne 1}`

D

`{z:abs(z)=1,z ne 1}`

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The correct Answer is:

D

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