If z^2+z+1=0 where z is a complex number...

If `z^2+z+1=0` where `z` is a complex number, then the value of `(z+1/z)^2+(z^2+1/z^2)^2+....+(z^6+1/z^6)^2` is

A

18

B

54

C

6

D

12

Verified by Experts

The correct Answer is:

D

Similar Questions

Explore conceptually related problems

If z is a complex number such that |z|>=2 then the minimum value of |z+1/2| is

Solve the equation z^2 +|z|=0 , where z is a complex number.

If z=(1+i)/(√2) , then the value of z^(1929) is

If z is a complex number satisfying the relation ∣z+1∣=z+2(1+i) then z is

If |z|=1 and z!=+-1, then all the values of z/(1-z^2) lie on

If z_1,z_2 and z_3,z_4 are two pairs of conjugate complex numbers then arg(z_1/z_4)+arg(z_2/z_3)=

For complex number z =3 -2i,z + bar z = 2i Im(z) .

If |z-2-3i|+|z+2-6i|=4 where i=sqrt(-1) then find the locus of P(z)

If |z-4/z|=2 then the greatest value of |z| is

Numbers of complex numbers z, such that abs(z)=1 and abs((z)/bar(z)+bar(z)/(z))=1 is