If |z|=1 and z!=+-1, then all the values...

If `|z|=1 and z!=+-1,` then all the values of `z/(1-z^2)` lie on

A

a line not passing through the origin

B

`abs(z)=sqrt(2)`

C

the X-axis

D

the Y-axis

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The correct Answer is:

D

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