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D=|[a, a^2, 0], [1, 2a+b, a+b],[ 0, 1, 2...

D=`|[a, a^2, 0], [1, 2a+b, a+b],[ 0, 1, 2a+3b]|` is divisible by
A) `a+b`
B) `a+2b`
C) `2a+3b`
D) `a^2`

A

A) (a+b) is a factor of f'(a,b)

B

(a+2b) is a factor of f'(a,b)

C

(2a+b) is a factor of f'(a,b)

D

a is a factor of f(a,b)

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
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