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A line OP through origin is inclined at...

A line OP through origin is inclined at `60^0` and `45^0` to OX and OY respectivey, where O is the origin. Find the angle at which it is inclined to OZ.

Text Solution

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The correct Answer is:
`r=|r|(pm(1)/(sqrt(3))hat(i)pm(1)/(sqrt(3))hat(j)pm(1)/(sqrt(3))hat(k))`
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