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Consider the equation of line AB is (x)/...

Consider the equation of line AB is `(x)/(2)=(y)/(-3)=(z)/(6)`. Through a point P(1, 2, 5) line PN is drawn perendicular to AB and line PQ is drawn parallel to the plane `3x+4y+5z=0` to meet AB is Q. Then,

A

coordinate of N are `((52)/(49), -(78)/(49), (156)/(49))`

B

the coordinate of Q are `(3, -(9)/(2), 9)`

C

the equation of PN is `(x-1)/(3)=(y-2)/(-176)=(z-5)/(-89)`

D

coordinate of N are `((156)/(49), (52)/(49), -(78)/(49))`

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(a, b, c)
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