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A sphere has the equation |r-a|^2+|r-b|^...

A sphere has the equation `|r-a|^2+|r-b|^2=72, where 'a=hat(i)+3hat(j)-6hat(k) and b=2hat(i)+4hat(j)+2hat(k)`
Find
(i) The centre of sphere
(ii) The radius of sphere
(iii) Perpendicular distance from the centre of the sphere to the plane `rcdot(2hat(i)+2hat(j)-hat(k))+3=0`.

Text Solution

Verified by Experts

The correct Answer is:
`(i) ((3)/(2), (7)/(2), -2), (ii) (sqrt(78))/(2) (iii)5`
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