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The shortest distance between any two op...

The shortest distance between any two opposite edges of the tetrahedron formed by planes `x+y=0, y+z=0, z+x=0, x+y+z=a` is constant, equal to

A

`2a`

B

`(2a)/(sqrt(6))`

C

`(a)/(sqrt(6))`

D

`(2a)/(sqrt(3))`

Text Solution

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The correct Answer is:
(b)
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