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Given the equation of the line 3x-y+z+1=...

Given the equation of the line `3x-y+z+1=0 and 5x-y+3z=0`. Then,which of the following is correct?

A

Symmetrical form of the equation of line is `(x)/(2)=(y-(1)/(8))/(-1)=(z+(5)/(8))/(1)`.

B

Symmetrical form of the equation of line is `(x+(1)/(8))/(1)=(y-(5)/(8))/(-1)=(z)/(-2)`

C

Equation of the plane through `(2, 1, 4)` and perpencular to the given lines is `2x-y+z-7=0`.

D

Equation of the plane through `(2, 1, 4)` and perpendicular to the given lines is `x+y-2z+5=0`.

Text Solution

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The correct Answer is:
(b, d)
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