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If `A(alpha, (1)/(alpha)), B(beta, (1)/(beta)), C(gamma,(1)/(gamma))` be the vertices of a `Delta ABC`, where `alpha, beta` are the roots of `x^(2)-6ax+2=0, beta, gamma` are the roots of `x^(2)-6bx+3=0` and `gamma, alpha` are the roots of `x^(2)-6cx + 6 =0`, a, b, c being positive.
The value of `a+b+c` is

A

`(-(1)/(2),-2)`

B

`(-(1)/(3),-3)`

C

`(-(1)/(5),-5)`

D

`(-(1)/(6),-6)`

Text Solution

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The correct Answer is:
D
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