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Transform the equation x^(2)-3xy+11x-12y...

Transform the equation `x^(2)-3xy+11x-12y+36=0` to parallel axes through the point (-4, 1) becomes `ax^(2)+bxy+1=0` then `b^(2)-a=`

A

`(1)/(4)`

B

`(1)/(16)`

C

`(1)/(64)`

D

`(1)/(256)`

Text Solution

Verified by Experts

The correct Answer is:
C
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