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Transform 12x^(2)+7xy-12y^(2)-17x-31y-7=...

Transform `12x^(2)+7xy-12y^(2)-17x-31y-7=0` to rectangular through the point (1, -1) inclined at an angle `tan^(-1)((4)/(3))` to the original axes.

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The correct Answer is:
xy = 0
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