Show that the centroid (x',y') of the tr...

Show that the centroid `(x',y')` of the triangle with sides `ax^2+2hxy+by^2=0` and `lx +my =1`, is given by
`(x')/(bl-hm)=(y')/(am-hl)=(2)/(3(am^2-2hlm+bl^2))`

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The correct Answer is:

`(x')/(bl-hm)=(y')/(am^2-2hlm+bl)=(2)/(3(am^2=2hlm+bl^2))`

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