Home
Class 12
MATHS
Area enclosed by curves y^2-5xy+6x^2+3...

Area enclosed by curves ` y^2-5xy+6x^2+3x-y=0 ` and `y^2-5xy+6x^2+2x-y=0` is `lambda` sq units , then the value of `lambda` is

Text Solution

Verified by Experts

The correct Answer is:
`(1)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Area of the triangle formed by the lines y^2-9xy+18x^2=0 and y=9 is

find the area enclosed by the curve y= -x^2 and the straight line x+y +2=0

if lambda x^2+10xy+3y^2-15x-21y+18=0 represents a pair of straight lines. Then , the value of lambda is

If the lines 2x+ y-3 = 0, 5x+ky - 3=0 and 3x -y -2 =0 are concurrent, find the value of k.

The area of the curve enclosed by the curve y^2 = 2x , Y -axis and line y=2 is ………..Sq . Units .

The area of the region enclosed by the curves y= sin x, y = cos and x=0 , x = (3pi)/(2) is ……Sq. units.

If parabolas y^2=lambdax and 25[(x-3)^2+(y+2)^2]=(3x-4y-2)^2 are equal, then the value of lambda is 9 (b) 3 (c) 7 (d) 6

If y is a function of x and log (x+y)=2xy , then the value of y'(0) is