Home
Class 12
MATHS
Find the equation of the parabola whose ...

Find the equation of the parabola whose latus-rectum is 4 units, axis is the line 3x+4y-4=0 and the tangent at the vertex is the line 4x-3y+7=0

Text Solution

Verified by Experts

The correct Answer is:
20(4x-3y+7)
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the parabola whose focus is (5,3) and directrix is the line 3x-4y+1=0.

Find equation of line whose y- intercept is (4)/(3) and perpendicular to the line 3x-4y+11=0 .

Find the equation of the normal to the parabola y^2=4x which is parallel to the line y=2x-5.

Find the equation of the tangent to the curve y^(2)=16x which is parallel to the line 4x-y=1 .

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

Find the equation of the tangent to the curve y=sqrt(3x-2) which is parallel to the line 4x-2y+5=0 .

Let V be the vertex and L be the latusrectum of the parabola x^2=2y+4x-4 . Then the equation of the parabola whose vertex is at V. Latusrectum L//2 and axis s perpendicular to the axis of the given parabola.

Find the equation of the normals to the curve y=x^(3)+2x+6 which are parallel to the line x+14y+4=0 .

Find the equation of the line passing through the point of intersection of the lines 4x+7y-3=0 and 2x-3y+1=0 that has equal intercepts on the axes.