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Show that the line xcos alpha+ysinalpha=...

Show that the line `xcos alpha+ysinalpha=p` touches the parabola `y^2=4ax` if `pcosalpha+asin^2alpha=0`
and that the point of contact is `(atan^2alpha,-2atanalpha)`.

Text Solution

Verified by Experts

The correct Answer is:
`(a tan ^2theta-2atanalpha)`
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