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If a line x+ y =1 cut the parabola y^2 =...

If a line `x+ y =1` cut the parabola `y^2 = 4ax` in points A and B and normals drawn at A and B meet at C. The normals to the parabola from C other than above two meets the parabola in D, then point D is :
(A) `(a,a)` (B) `(2a,2a)` (C) `(3a,3a)` (D) `(4a,4a)`

A

(a,2a)

B

`((4am)/l^2,(4a)/l)`

C

`((2am^2)/l^2,(2a)/l)`

D

`((4am^2)/l^2,(4am)/l)`

Text Solution

Verified by Experts

The correct Answer is:
D
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