Home
Class 12
MATHS
The equation of the latusrectum of the p...

The equation of the latusrectum of the parabola `x^2+4x+2y=0` is

A

3y-2=0

B

3y+2=0

C

2y-3=0

D

2y+3=0

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

The tangents and normals are drawn at the extremites of the latusrectum of the parabola y^2=4x . The area of quadrilateral so formed is lamda sq units, the value of lamda is

The focus of the parabola x^2-8x+2y+7=0 is

The directrix of the parabola x^2-4x-8y + 12=0 is

Let V be the vertex and L be the latusrectum of the parabola x^2=2y+4x-4 . Then the equation of the parabola whose vertex is at V. Latusrectum L//2 and axis s perpendicular to the axis of the given parabola.

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.

Find the equation of the normal to the parabola y^2=4x which is parallel to the line y=2x-5.

The length of the latusrectum of the parbola whose focus is (3, 3) and directrix 3x-4y-2=0, is

The set of points on the axis of the parabola y^2-4x-2y+5=0 from which all the three normals to the parabola are real , is

The equation of a tangent to the parabola y^2=8x is y=x+2 . The point on this line from which the other tangent to the parabola is perpendicular to the given tangent is (1) (-1,""1) (2) (0,""2) (3) (2,""4) (4) (-2,""0)

The equations of the common tangents to the parabola y = x^2 and y=-(x-2)^2 is/are :