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If a!=0 and the line 2bx+3cy+4d=0 passes...

If `a!=0` and the line `2bx+3cy+4d=0` passes through the points of intersection of the parabola `y^2 = 4ax` and `x^2 = 4ay`, then

A

(a) `d^2+(2b+3c)^2=0`

B

(b) `d^2+(3b+2c)^2=a^2`

C

(c) `d^2+(2b-3c)^2=0`

D

(d) `d^2+(2b+3c)^2=a^2`

Text Solution

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The correct Answer is:
A
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