Home
Class 12
MATHS
The locus of foot of the perpendiculars ...

The locus of foot of the perpendiculars drawn from the vertex on a variable tangent to the parabola `y^2 = 4ax` is

A

the directrix

B

the tangent at the vertex

C

x=a

D

x=0

Text Solution

Verified by Experts

The correct Answer is:
B, D
Promotional Banner

Similar Questions

Explore conceptually related problems

The common tangent to the parabola y^2=4ax and x^2=4ay is

The coordinates of the foot of the perpendicular drawn from the origin to the plane 2x -3y +4z -6=0 are ……

Find the coordinates of the foot of the perpendicular drawn from the origin to the plane 2x – 3y + 4z - 6 = 0.

The vertex of the parabola y^2+6x-2y+13=0 is

Find the equation of the perpendicular drawn from the origin to the plane 2x+4y-5z=10 .

Show that the locus of points such that two of the three normals drawn from them to the parabola y^2 = 4ax coincide is 27ay^2 = 4(x-2a)^3 .

If P be a point on the parabola y^2=3(2x-3) and M is the foot of perpendicular drawn from the point P on the directrix of the parabola, then length of each sides of an equilateral triangle SMP(where S is the focus of the parabola), is

The foot of perpendicular drawn from the origin to the plane 2x + 3y + 4z - 12 = 0 is..........

The locus of the mid-point of the focal radii of avariable point moving on the parabola, y^2= 4ax is C, then the length of latus rectum of C, is