Tangent to the curve y=x^2+6 at a point ...

Tangent to the curve `y=x^2+6` at a point `(1,7)` touches the circle `x^2+y^2+16x+12y+c=0 `at a point `Q`, then the coordinates of `Q` are (A) `(-6,-11)` (B) `(-9,-13)` (C) `(-10,-15)` (D) `(-6,-7)`

A

(-6,-11)

B

(-9,-13)

C

(-10,-15)

D

(-6,-7)

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The correct Answer is:

D

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