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Let P be the point on parabola y^2=4x wh...

Let P be the point on parabola `y^2=4x` which is at the shortest distance from the center S of the circle `x^2+y^2-4x-16y+64=0` let Q be the point on the circle dividing the line segment SP internally. Then

A

`SP=2sqrt5`

B

`SQ:QP=(sqrt5+1):2`

C

the x-intercept of the normal to the parabola at P is 6

D

the slope of the tangent to the circle at Q is `1/2`

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A, C, D
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