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If lim(x to 0)[1+x ln(1+b^2)]^(1/x)=2bs...

If `lim_(x to 0)[1+x ln(1+b^2)]^(1/x)=2bsin^2theta,b >0, and theta in (-pi,pi],` then the value of `theta` is

A

`+-(pi)/4`

B

`+-(pi)/3`

C

`+-(pi)/6`

D

`+-(pi)/2`

Text Solution

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The correct Answer is:
D
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