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Let f(x+y)=f(x)+f(y) for all xa n dydot ...

Let `f(x+y)=f(x)+f(y)` for all `xa n dydot` If the function `f(x)` is continuous at `x=0,` show that `f(x)` is continuous for all `xdot`

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The correct Answer is:
Therefore, function is continuous for all values of x, if it is continuous at 0.
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