Let f : R -> R is a function satisfying...

Let `f : R -> R` is a function satisfying `f(2-x) = f(2 + x) and f(20-x)=f(x),AA x in R`. On the basis of above information, answer the following questions If `f(0)=5`, then minimum possible number of values of x satisfying `f(x) = 5`, for `x in [0, 170]` is

Verified by Experts

The correct Answer is:

9

Similar Questions

Explore conceptually related problems

The number or linear functions f satisfying f(x+f(x))=x+f(x) AA x in RR is

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

Let f:R->R be a function such that f(x+y)=f(x)+f(y),AA x, y in R.

Let f be a function satisfying f(x+y)=f(x) + f(y) for all x,y in R . If f (1)= k then f(n), n in N is equal to

Let f : R rarr R be the function defined by f(x) = 1/(2-cosx),AA x inR . Then , find the range of f .

If f:R rarr R is continuous function satisfying f(0) =1 and f(2x) -f(x) =x, AAx in R , then lim_(nrarroo) (f(x)-f((x)/(2^(n)))) is equal to

Let f : R rarr R be the function defined by f(x) = 2x - 2 , AA x in R . Write f^(-1) .

If a function satisfies f(x+1)+f(x-1)=sqrt(2)f(x) , then period of f(x) can be

For x inR - {1} , the function f(x ) satisfies f(x) + 2f(1/(1-x))=x . Find f(2) .

If f is polynomial function satisfying 2+f(x)f(y)=f(x)+f(y)+f(x y)AAx , y in R and if f(2)=5, then find the value of f(f(2))