x ની સાપેક્ષ વિકલન શોધો :`tan^-1((a cos x - b sin x)/(b cosx +asin x)),-pi/2 < x < pi/2` અને `a/b tanx> -1`

Differentiate, tan^(-1) ((a cos x- b sin x)/(b cos x + a sin x)), (-pi)/(2) lt x lt (pi)/(2) and (a)/(b) tan x gt -1

Find (dy)/(dx) in the following: y= tan^(-1) ((a cos x- b sin x)/(b cos x + a sin x))

(sin x + sin 3x )/( cos x + cos 3x )= tan 2x

cos(2pi -x) cos (-x) - sin(2pi +x) sin (-x) = 0

Let (b cos x)/(2 cos 2x-1)=(b + sin x)/((cos^(2) x-3 sin^(2) x) tan x), b in R . Equation has solutions if

Prove that (sinx+sin3x)/(cosx+cos3x)=tan2x

cos 2x- 3 cos x + 1=(1)/((cot 2 x - cot x)sin (x-pi)) holds , if