જો x=sec theta - cos theta ,y=sec^n thet...

જો `x=sec theta - cos theta ,y=sec^n theta -cos ^ n theta `તો સાબિત કરો કે .`(x^2+4)(dy/dx)^2=n^2(y^2+4)`

A

`n^(2)(y^(2)-4)`

B

`n^(2)(4-y^(2))`

C

`n^(2)(y^(2)+4)`

D

None of these

Verified by Experts

The correct Answer is:

C

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