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જો f(x)={(1+x, 0 le x le 2),(3-x, 2< x ...

જો `f(x)={(1+x, 0 le x le 2),(3-x, 2< x le3):}` તો વિધેય fof કેટલા બિંદુએ વિકલનીય ના થાય?

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The correct Answer is:
`(fof)(x)={{:(2+x",", 0 lex le 1),(2-x",", 1 lt x le 2),(4-x",", 2 lt x le 3):}`
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