Let f :[1/2,oo)rarr[3/4,oo), where f(x)=...

Let `f :[1/2,oo)rarr[3/4,oo),` where `f(x)=x^2-x+1.` Find the inverse of f(x). Hence or otherwise solve the equation, `x^2-x+1=1/2+sqrt(x-3/4.`

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The correct Answer is:

x=1 is the required solution.

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