If 3(a+2c)=4(b+3d), then the equation a ...

If `3(a+2c)=4(b+3d),` then the equation `a x^3+b x^2+c x+d=0` will have (a) no real solution (b) at least one real root in `(-1,0)` (c)at least one real root in `(0,1)` (d)none of these

A

no real solution

B

atleast one real root in `(-1, 0)`

C

atleast one real root in `(0, 1)`

D

None of the above

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The correct Answer is:

B

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