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Perpendiculars are drawn from the angles...

Perpendiculars are drawn from the angles `A, B and C` of an acute-angled triangle onthe opposite sides, and produced to meet the circumscribing circle. If these produced parts are `alpha., beta, gamma,` respectively, then show that, then show that `a/alpha+b/beta+c/gamma=2(tanA+tanB+tanC).`

Text Solution

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The correct Answer is:
`(a)/(alpha) +(b)/(beta)+ (c)/(gamma) =2 (tan A+ tan B+ tan C)`
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