If a = cos theta + isin theta, b = cosph...

If `a = cos theta + isin theta`, `b = cosphi + isinphi`, `c = cos psi + i sin psi` and `a/b+b/c+c/a=2` then `sin(theta-phi)+sin(phi-psi)+sin(psi-theta)` equals

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The correct Answer is:

`tan ^(2) ""(theta)/(2)+ tan ^(2)""(phi)/(2)+ tan ^(2)""(Psi)/(2)=1`

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