In a `Delta ABC, if a =3, b=4, c=5,` then find the distance between its incentre and circumcentre.

The vertices of a triangle are (6, 0), (0, 6) and (6, 6). Then distance between its circumcentre and centroid, is

The vertices of a triangle are A(0, 0), B(0, 2) and C(2, 0). The distance between circumcentre and orthocentre is

Find distance between the points A(3, 4) and B(-4, 3).

(1,2),(2,1), ((3+ sqrt(3))/( 2) , (3 + sqrt3)/( 2) ) are verticies of triangle. Then distance between circumcentre and orthocentre is ........ ..

In a Delta ABC, a =2b and |A-B| =(pi)/(3). Determine the angleC.

In a triangle ABC, sin A- cos B = Cos C , then angle B is

A and B are two points given by (8, 3), (-4, 3). Find the distance between A and B.

Statement I : If centroid and circumcentre of a triangle are known its orthocentre can be found Statement II : Centroid, orthocentre and circumcentre of a triangle are collinear.

A(0, 0), ,.B (-36, 15) and C(20, 15) are the verticies of Delta ABC . Find centroid, incentre, circum centre and ortho centre of Delta ABC .

Consider a Delta ABC and let a,b, and c denote the leghts of the sides opposite to vertices A,B and C, respectively. Suppose a=2,b =3, c=4 and H be the orthocentre. Find 15(HA)^(2).