Let `PQR` be a triangle of area `Delta` with `a = 2, b = 7/2 and c =5/2,` where `a, b and c` are the lengths of the sides of the triangle opposite to the angles at `P, Q and R` respectively. Then `(2sinP-sin2P)/(2sinP+sin2P)` equals

Options

A. ` (3)/(4 Delta)`
B. `(45)/(4 Delta)`
C. `((3)/(4 Delta))^(2)`
D. `((45)/(4Delta))^(5)`

Answer

B, C, D