Let f : R to [0, pi/2) be defined by f ...

Let `f : R to [0, pi/2)` be defined by `f ( x) = tan^(-1) ( 3x^(2) + 6x + a)". If " f(x)` is an onto function . then the value of a is

A

1

B

2

C

3

D

4

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

Let f:R to R be defined by f(x)=3x-4 . Then, f^(-1) (x) is

Let the f : R to R be defined by f(x)=2x+cos x , then f …………….

If f:R rarr [pi/6,pi/2], f(x)=sin^(-1)((x^(2)-a)/(x^(2)+1)) is an onto function, the set of values a is

Let f : R rarr R be the function defined by f(x) = 2x - 2 , AA x in R . Write f^(-1) .

f:R to R is a function defined by f(x)= 10x -7, if g=f^(-1) then g(x)=

Let f(x) = tan^(-1)(((x-2))/(x^(2)+2x+2)) ,then 26 f'(1) is

f: R rarr R, f(x) = sec^(2)x - tan^(2) x is constant function .

Let the function f : R rarr R be defined by f(x) = cos x , AA x in R . Show that f is nether one - one nor onto .