Expand `(2a - (3)/(b))^(5)` by binomial theorem

Explanation

Using binomial theorem , we get
`(2a - (3)/(b))^(5) = ""^(3)C_(0) (2a)^(5-0) (-(3)/(b))^(0) + ""^(5)C_(1) (2a)^(5-1)(-(3)/(b))^(1)`
` + ""^(5)C_(2) (2a)^(5-2)(-(3)/(b))^(2) + ""^(5)C_(3)(2a)^(5-3) (-(3)/(b))^(3)`
` + ""^(5)C_(4)(2a)^(5-4) (-(3)/(b))^(4)`
` + ""^(5)C_(5) (2a)^(5-5) (-(3)/(b))^(5)`
` = ""^(5)C_(0) (2a)^(5) - ""^(5)C_(1)(2a)^(4) ((3)/(b)) + ""^(5)C_(2) (2a)^(3) ((3)/(b))^(2)`
`- ""^(5)C_(0) (2a)^(2) ((3)/(b))^(3) + ""^(5)C_(4) (2a)^(3) ((3)/(b))^(4) - ""^(5)C_(5) ((3)/(b))^(5)`
`= 32a^(5) - (240a^(4))/(b) + (720a^(3))/(b^(2)) - (1080 a^(2))/(b^(3)) + (810a)/(b^(4)) + (243)/(b^(5))` .