Show that
`1992^(1998) - 1955^(1998) - 1938^(1998) + 1901^(1998)` is divisible by 1998

Explanation

Here ,n = 1998 (Even )
` therefore ` Only result (i) applicable
Let `P= 1992^(1998) - 1995^(1998) - 1938^(1998) + 1901^(1998)`
`= (1992^(1998) - 1995^(1998)) - (1938^(1998) + 1901^(1998))`
`{:("disivible by (1992 - 1955) "," divisible by (1938 - 1901") ,(i.e. 37,i.e.37):}`
` therefore ` P is divisible by 37 .
Also ` P= (1992^(1998) - 1938^(1998)) - (1955^(1998) -1901^(1998))`
`{: ("disivible by (1992 - 1955) "," divisible by (1938 - 1901") ,(i.e. 37,i.e.37):}`
`therefore` P is also divisaible by 54
Hence , P is divisible by ` 37 xx 54`, i.e, 1998.