The equation to the straight line passing through the point `(a "cos"^(3) theta, a "sin"^(3) theta)` and perpendicular to the line `x "sec" theta + y"cosec" theta = a` is

Equation of the line passing through the point ( a cos^(3) theta , a sin^(3) theta ) and perpendicular to the line x sec theta + y cosec theta = a is x cos theta - y sin theta = cos 2 theta .

The equation of the straight line passing through the point (3,2) and perpendicular to the line y=x is,

Show that cot theta +tan theta =sec theta cosec theta

0 lt theta lt (pi)/(2) then the minimum value of sin^(3) theta + cosec^(3) theta is……

z=i+sqrt(3)=r(cos theta+sin theta)

Find (dy)/(dx) : x=a sec^(3) theta, y= a tan^(3) theta

Find the slope of the normal to the curve x = a cos^(3)theta, y=a sin^(3)theta at theta = (pi)/(4) .

Find perpendicular distance from the origin to the line joining the points ( cos theta , sin theta ) and ( cos phi, sin phi) .