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If the lines (a-b-c) x + 2ay + 2a = 0 , ...

If the lines `(a-b-c) x + 2ay + 2a = 0 , 2bx + ( b- c - a) y + 2b = 0 and (2c+1) x + 2cy + c - a - b = 0 ` are concurrent , then the prove that either `a+b+ c = 0 or (a+b+c)^(2) + 2a = 0 `

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