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If (d)/(dx)[ x^(n+1)+c]=(n+1)x^(n), then...

If `(d)/(dx)[ x^(n+1)+c]=(n+1)x^(n)`, then find `int x^(n)dx`.

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The correct Answer is:
`:.int x^(n)dx=(x^(n+1))/(n+1)+C`
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